Welcome to our lesson, "Identifying and Fixing Logical Errors in Java". Today, we are going to unravel the logical errors that, although valid according to the rules of the Java language, do not deliver the output we expect.
Logical errors can be elusive because neither the Java compiler nor the CodeSignal IDE can directly help identify them. However, once you learn to spot them, finding and fixing logical errors can become quite intriguing.
We will unravel the mystery of logical errors, looking into their definition and types and the process of rectifying them using the debugging tools. By the end of this lesson, you will be navigating through the Java galaxy, resolving logical errors with ease.
Logical errors can be likened to an instance where you follow a recipe to the letter, measuring all ingredients precisely, only to end up with a dish that doesn't taste as expected. In programming terms, the syntax of your code is flawless, and the program runs without any glitches, but the output isn't what you intended.
Let's explore an example in Java:
Java1int width = 5; 2int height = 10; 3int area = width + height; //logical error 4System.out.println("Area of the rectangle: " + area);
In this instance, we have mistakenly added the width
and height
of a rectangle, but the area of a rectangle should be calculated by multiplying them. Although the program runs without any error, it yields an incorrect output. Thus, this is a logical error.
You may encounter several common logical errors:
Java1int[] numbers = {1, 2, 3, 4, 5}; 2for (int i = 1; i <= numbers.length; i++) { 3 System.out.println(numbers[i]); 4}
This loop should print the integers 1 to 5 (a total of 5 integers) but ends up with a runtime error accessing the non-existing index numbers.length
due to an Off-by-One Error.
Java1int number = 0; 2while (number < 10) { 3 System.out.println(number); 4}
The above loop is an example of an infinite loop. The exit condition (number < 10
) will always remain constant, as the number
doesn't change inside the loop, leading to an infinite loop.
Java1int a = 5; 2int b = 5; 3int divisor = a - b; 4int dividend = 5; 5int quotient = dividend / divisor;
The above code, in which you attempt to divide a number by zero, is an example of a logical error that causes a runtime error.
Debugging to find a logical error involves thinking through your code, adding debug output (via System.out.println
or using IDE debugging tools), analyzing this output, and reasoning out why it is behaving in such a manner. Here are the corrected versions of the errors we just mentioned:
Java1int[] numbers = {1, 2, 3, 4, 5}; 2for (int i = 1; i < numbers.length; i++) { 3 System.out.println(i); // debugging output - helped us to see that we are entering the loop with `i = numbers.length` that's not expected 4 System.out.println(numbers[i]); 5}
Java1int number = 0; 2while (number < 10) { 3 System.out.println(number); // this print statement itself was a great debugging mechanism, we could see the number doesn't change 4 number++; // adding the missing statement 5}
Java1int a = 5; 2int b = 5; 3int divisor = a - b; 4int dividend = 5; 5System.out.println("Dividing " + dividend + " by " + divisor); // Adding a debug statement to see that we are dividing by 0 6int quotient = dividend / (divisor + 1);
Today, we engaged in a detailed examination of logical errors in Java programming, how these errors differ from other types, commonly encountered logical errors, and techniques to debug them. Now, it's time for hands-on practice to reinforce your newfound knowledge about logical errors. Let the practice exercises guide you through the fog of logical errors. Remember, practice makes perfect! Enjoy the process of debugging!