Hello, and welcome, code explorer! Today's journey takes us through the intricate paths within a 2-dimensional array, often likened to a game board. Our mission is to identify ideal spots for game piece placement. Sounds like an adventure, doesn't it? Let's embark!
Visualize a chessboard in the form of a 2D array, where each cell could be marked E
for empty or P
for a piece. Our quest involves summoning a TypeScript function named findPositions()
. This function is defined as function findPositions(board: string[][]): [number, number][]
. Upon examining this 2D array, it identifies all the spots where a new piece could be placed so that it can move to another empty cell in one move. The catch is that a piece can move only to an immediately neighboring cell directly above, below, to the left, or right, but not diagonally.
Consider this 4x4 board, for instance:
1P E E P 2E P E P 3P E P P 4P E P E
The function should output the following pairs representing positions: (0, 1), (0, 2), (1, 2), (2, 1), (3, 1)
. This output represents the positions where a piece could be placed (empty) and then be able to move to a new empty spot in the next turn.
Stepping right into action, we start with an empty positions
array to help us log the sought positions. Understanding the dimensions of our "board" paves the way for defining boundaries in our exploration mission. The positions
array is initialized as let positions: [number, number][] = [];
. Additionally, we determine the size of the 2D array using the length
property.
Using an array is crucial here because we don't know beforehand how many positions will be found. An array in TypeScript can dynamically adjust its size to accommodate any number of elements, making it a perfect choice for storing an unknown number of positions.
TypeScript1function findPositions(board: string[][]): [number, number][] { 2 let positions: [number, number][] = []; 3 4 let rows: number = board.length; 5 let cols: number = board[0].length; 6 // Further exploration follows
With the dimensions defined, we begin our expedition across the board. We use two nested for
loops to do this, employing TypeScript's static typing for loop variables (i: number, j: number)
to traverse the entire board one cell at a time.
TypeScript1function findPositions(board: string[][]): [number, number][] { 2 let positions: [number, number][] = []; 3 4 let rows: number = board.length; 5 let cols: number = board[0].length; 6 7 for (let i: number = 0; i < rows; i++) { 8 for (let j: number = 0; j < cols; j++) { 9 // ensuing exploration
What's the plan for each cell, you ask? While exploring each cell, our trusty TypeScript code inspects if the cell is empty. If confirmed, it then peeks into the neighbors in the up, down, left, and right directions. If another vacant cell (E
) is spotted, we jot down the main cell's position in our positions
array.
TypeScript1function findPositions(board: string[][]): [number, number][] { 2 let positions: [number, number][] = []; 3 4 let rows: number = board.length; 5 let cols: number = board[0].length; 6 7 for (let i: number = 0; i < rows; i++) { 8 for (let j: number = 0; j < cols; j++) { 9 if (board[i][j] === 'E') { 10 if ((i > 0 && board[i - 1][j] === 'E') || 11 (i < rows - 1 && board[i + 1][j] === 'E') || 12 (j > 0 && board[i][j - 1] === 'E') || 13 (j < cols - 1 && board[i][j + 1] === 'E')) { 14 positions.push([i, j]); 15 } 16 } 17 } 18 } 19 return positions; 20} 21 22let board: string[][] = [ 23 ['P', 'E', 'E', 'P'], 24 ['E', 'P', 'E', 'P'], 25 ['P', 'E', 'P', 'P'], 26 ['P', 'E', 'P', 'E'] 27]; 28 29let positions: [number, number][] = findPositions(board); 30 31for (let i: number = 0; i < positions.length; i++) { 32 console.log(`(${positions[i][0]}, ${positions[i][1]})`); 33} 34 35// The output will be: 36// (0, 1) 37// (0, 2) 38// (1, 2) 39// (2, 1) 40// (3, 1)
Neatly wrapped up, haven't we? Today we engaged in a thrilling treasure hunt and emerged victorious with the positions
array. This journey revealed the importance of understanding 2D arrays and effectively maneuvering through them using TypeScript. With TypeScript’s type safety, we reduced the chances of runtime errors, enhancing the robustness of our code. The explicit type annotations not only made our code more readable but also more dependable. Now that we've mastered the theory, we step into the realm of application — the practice field. Venture forth and make your mark by solving correlated challenges. And remember, persistence is the best companion for a coder. Happy coding!