Hello there! Are you ready to enhance your Go programming skills with another exciting exercise? In this unit, we are plunging into the world of matrices. More specifically, we'll be transposing a given matrix. Let's dive into this matrix manipulation without delay!
To begin, let's elaborate on the task at hand. You are required to write a Go function named TransposeMatrix()
. This function will accept a 2D slice of integers (which represents a matrix) as input. Your responsibility is to return another 2D slice of integers, which is the transposed version of the given matrix.
Remember, when we mention 'transposing a matrix,' we are referring to the process of switching its rows and columns. In other words, all the rows of the original matrix should be converted into columns in the transposed matrix, and vice versa.
For instance, if the original matrix (input 2D slice) is:
Go1matrix := [][]int{ 2 {1, 2, 3}, 3 {4, 5, 6}, 4}
Then the transposed matrix (output 2D slice) will be:
Go1transposed := [][]int{ 2 {1, 4}, 3 {2, 5}, 4 {3, 6}, 5}
It is vital for your result to maintain the integrity of the data type present in the original matrix. The values in the input matrix are integers, and they should be integers in the output matrix as well.
The initial step in building our solution involves determining the dimensions of the matrix. We need to know the number of rows and columns present in it. In Go, you can use the len
function to obtain this information. The number of rows is given by len(matrix)
, and the number of columns by len(matrix[0])
.
Go1package main 2 3import "fmt" 4 5func TransposeMatrix(matrix [][]int) [][]int { 6 rows := len(matrix) 7 cols := len(matrix[0]) 8}
The subsequent step is to create a "placeholder" for the transposed matrix that aligns with its required dimensions. This will be a new 2D slice, but with the number of rows and columns swapped. Initially, we can populate this slice with all zeros.
Go1package main 2 3import "fmt" 4 5func TransposeMatrix(matrix [][]int) [][]int { 6 rows := len(matrix) 7 cols := len(matrix[0]) 8 result := make([][]int, cols) 9 for i := range result { 10 result[i] = make([]int, rows) 11 } 12}
It's time to get to the crux of the matter — transposing the matrix. For every element in the original matrix, we want to move it from the i
th row and j
th column to the j
th row and i
th column of the transposed matrix. A straightforward nested for
loop can effortlessly execute this swap for all elements of the matrix.
Go1package main 2 3import "fmt" 4 5func TransposeMatrix(matrix [][]int) [][]int { 6 rows := len(matrix) 7 cols := len(matrix[0]) 8 result := make([][]int, cols) 9 for i := range result { 10 result[i] = make([]int, rows) 11 } 12 13 for i := 0; i < rows; i++ { 14 for j := 0; j < cols; j++ { 15 result[j][i] = matrix[i][j] 16 } 17 } 18 return result 19} 20 21func main() { 22 // Initial matrix (2D slice) 23 matrix := [][]int{ 24 {1, 2, 3}, 25 {4, 5, 6}, 26 } 27 28 // Call our function on the matrix and output the result 29 transposed := TransposeMatrix(matrix) 30 for i := 0; i < len(transposed); i++ { 31 for j := 0; j < len(transposed[i]); j++ { 32 fmt.Print(transposed[i][j], " ") 33 } 34 fmt.Println() 35 } 36}
This step concludes our solution!
With this, we've brought this lesson to a close! Congratulations on successfully implementing a function that can transpose matrices! This task is not simple, but by accomplishing it, you've exhibited your understanding of and proficiency in Go multidimensional slices, for
loops, and the concept of matrix transposition.
Your hard work continues, though. Now that you have acquired this valuable skill, it's time to reinforce it with more practice. During the next session, you will encounter practice problems that build on this concept. So, get ready and start coding!