Welcome to a delightful lesson on array traversal! In this lesson, we invite you to join an endearing bunny named Gloria on an intricate quest. Gloria has a soft spot for number games, especially when they involve hopping between arrays. Our goal on this exciting journey is to assist Gloria through her escapade and identify the maximum value she encounters along the way. Are you ready to embark on this adventure?
Gloria's quest unfolds with two arrays, both brimming with non-negative integers. Starting at the first element of arrayA
, she leaps to arrayB
based on the index she discovers in arrayA
. She then bounces back to arrayA
according to the index she stumbles upon in arrayB
. Gloria repeats these hops until she returns to where she started in arrayA
. What an adventure!
Your challenge is to craft a Java function that aids Gloria on her trip. The function will take two arrays of integers as inputs, representing arrayA
and arrayB
. The objective is to find the highest value from arrayB
that Gloria jumps to during her voyage.
It is guaranteed that, at some point, Gloria returns to the starting position.
Example
If arrayA = {2, 4, 3, 1, 6}
and arrayB = {4, 0, 3, 2, 0}
, the output should be 3
.
In this scenario, Gloria starts from the first element of arrayA
, which is 2
. Then, she jumps to arrayB
at index 2
, where she discovers 3
. She then bounces back to arrayA
at index 3
, where she arrives at 1
. From there, she leaps back to arrayB
at index 1
, stumbling upon a 0
. Finally, she bounces back to arrayA
at index 0
, the location where she started her adventure. Hence, she stops here. During this journey, she encountered the highest value 3
from arrayB
.
Before we make headway with our code, let's kickstart with the initialization of variables. Let indexA
and indexB
denote the last positions of Gloria in arrayA
and arrayB
, respectively. We will also use max_value
for tracking the highest value encountered in arrayB
. Her quest starts from arrayA
, so we also maintain a Boolean flag in_arrayA
.
Java1int indexA = 0; 2int indexB = -1; 3boolean in_arrayA = true; 4int max_value = Integer.MIN_VALUE;
Our assistant for Gloria’s hopping challenge will be a while
loop! This keeps iterating until Gloria returns to her starting position in arrayA
.
If Gloria is in arrayA
, we check if the value in arrayB
where she is going to land is greater than max_value
and update max_value
if it is. We also switch Gloria's position to the other array in each iteration.
Java1while (true) { 2 if (in_arrayA) { 3 indexB = arrayA[indexA]; 4 if (arrayB[indexB] > max_value) { 5 max_value = arrayB[indexB]; 6 } 7 } else { 8 indexA = arrayB[indexB]; 9 if (indexA == 0) { 10 return max_value; 11 } 12 } 13 in_arrayA = !in_arrayA; 14}
Collecting all the pieces together, here’s our ultimate function:
Java1public class GloriaArrayTraversal { 2 public static int solution(int[] arrayA, int[] arrayB) { 3 int indexA = 0; 4 int indexB = -1; 5 boolean in_arrayA = true; 6 int max_value = Integer.MIN_VALUE; 7 8 while (true) { 9 if (in_arrayA) { 10 indexB = arrayA[indexA]; 11 if (arrayB[indexB] > max_value) { 12 max_value = arrayB[indexB]; 13 } 14 } else { 15 indexA = arrayB[indexB]; 16 if (indexA == 0) { 17 return max_value; 18 } 19 } 20 in_arrayA = !in_arrayA; 21 } 22 } 23 24 public static void main(String[] args) { 25 int[] arrayA = {2, 4, 3, 1, 6}; 26 int[] arrayB = {4, 0, 3, 2, 0}; 27 28 System.out.println("Maximum value encountered in arrayB: " + solution(arrayA, arrayB)); 29 // Prints: 30 // Maximum value encountered in arrayB: 3 31 } 32}
Heartiest congratulations on guiding Gloria through her array-hopping adventure. Not only have you heightened Gloria's joy, but you've also skillfully solved a complex task. You've deftly handled arrays, tracked indices, and made careful use of conditional statements.
This experience should empower you to take on more complex coding challenges. Keep practicing, keep exploring, and keep growing. Happy coding!