Welcome to today's lesson, where we will confront a common challenge in software engineering: the introduction of complex features while preserving backward compatibility. We'll use a Potluck Dinner organization system as our backdrop, embarking on a fascinating journey of Python programming, step-by-step analysis, and strategic thinking. Are you ready? Let's begin our adventure!
Initially, our Potluck Dinner organization system enables us to add and remove participants and manage their respective dishes for each round. There are three critical methods:
add_participant(self, member_id: str) -> bool
: This method adds a participant. If a participant with the given member_id
already exists, it won't create a new one but will return False
. Otherwise, it will add the member and return True
.remove_participant(self, member_id: str) -> bool
: This method removes a participant with the given member_id
. If the participant exists, the system will remove them and return True
. Otherwise, it will return False
. When removing a participant, you need to remove their dish if they brought one.add_dish(self, member_id: str, dish_name: str) -> bool
: This method enables each participant to add their dishes for every round. If a participant has already added a dish for this round OR if the member_id
isn't valid, the method will return False
. Otherwise, it will add the dish for the respective participant's round and return True
.Let's write our Python code, which implements the functions as per our initial state:
Python1class Potluck: 2 3 def __init__(self): 4 self.participants = set() 5 self.dishes = {} 6 7 def add_participant(self, member_id: str) -> bool: 8 if member_id in self.participants: 9 return False 10 else: 11 self.participants.add(member_id) 12 return True 13 14 def remove_participant(self, member_id: str) -> bool: 15 if member_id not in self.participants: 16 return False 17 else: 18 self.participants.remove(member_id) 19 def self.dishes[member_id] 20 return True 21 22 def add_dish(self, member_id: str, dish_name: str) -> bool: 23 if member_id not in self.participants or member_id in self.dishes: 24 return False 25 else: 26 self.dishes[member_id] = dish_name 27 return True
In this code, we employed a Python set
to store unique participant IDs and a Python dictionary
to store the participant's ID and their respective dish name. With this foundation laid, let's introduce some advanced functionalities.
Our Potluck Dinner organization system is currently simple but practical. To make it even more exciting, we're going to introduce a "Dish of the Day" feature. This feature will enable participants to vote, and the dish receiving the most votes will be declared the "Dish of the Day".
To add this feature, we will define two new methods:
vote(self, member_id: str, vote_id: str) -> bool
: This method will allow a participant to cast a vote for a dish. Each participant can cast a vote only once per round. If a participant tries to vote again or if the member_id
isn't valid, it should return False
.dish_of_the_day(self) -> str | None
: This method will calculate and return the "Dish of the Day" based on the votes received. If multiple dishes tie for the highest number of votes, the dish brought by the participant who joined first acquires precedence. If there are no votes, the function returns None
.Next, we will extend our existing Potluck
class to accommodate these new features:
Python1class Potluck: 2 3 def __init__(self): 4 self.participants = {} 5 self.dishes = {} 6 self.votes = {}
Firstly, we altered our participants
data structure into a dictionary
, where the key is the participant's id and the value is the time of joining (we use the time of adding to the system as the join time).
We also added a votes
dictionary to store the votes, where the key is the participant id and the value is the participant id for whom they have cast the vote.
Python1 def vote(self, member_id: str, vote_id: str) -> bool: 2 if member_id in self.participants and member_id not in self.votes: 3 self.votes[member_id] = vote_id 4 return True 5 else: 6 return False
In the vote function, we simply checked whether the member_id
exists and whether the vote hasn't been cast before. If both conditions are fulfilled, we add the vote to our votes and return True
; otherwise, we return False
.
Python1 def dish_of_the_day(self) -> str | None: 2 votes = list(self.votes.values()) 3 if not votes: 4 return None 5 vote_count = {i: votes.count(i) for i in votes} 6 max_votes = max(vote_count.values()) 7 max_vote_dishes = [k for k, v in vote_count.items() if v == max_votes] 8 earliest_join_time = min([self.participants[i] for i in max_vote_dishes]) 9 dish_of_the_day_member = [k for k in max_vote_dishes if self.participants[k] == earliest_join_time][0] 10 return f"Participant: '{dish_of_the_day_member}', Dish: '{self.dishes[dish_of_the_day_member]}'" 11
In the dish_of_the_day
function, we start by ensuring we perform the calculation only if there are votes. Afterward, we calculate the count of votes for each dish, determine the dish or dishes that have received the maximum votes, and if there's a tie, we select the dish brought by the participant who joined the earliest. Finally, we return the selected "Dish of the Day".
As we introduce the two advanced functionalities, vote
and dish_of_the_day
, our existing system needs to be adeptly updated to ensure seamless integration while maintaining backward compatibility. Here's how we've refined the previous methods:
The add_participant
method initially just added a participant to a set. With the introduction of the "Dish of the Day" feature, we now store the participant ID along with their join time in a dictionary. This timestamp is crucial for determining the precedence in case of a tie in votes.
Python1import time 2 3def add_participant(self, member_id: str) -> bool: 4 if member_id in self.participants: 5 return False 6 else: 7 self.participants[member_id] = time.time() 8 return True
This adjustment ensures that every new participant is tracked with a join time, allowing us to leverage this information for the "Dish of the Day" feature.
The original remove_participant
method did not consider the impact of removing a participant who might have already voted or added a dish. To maintain the integrity of our voting and dish tracking, we now clean up all related entries across dishes
and votes
dictionaries when a participant is removed.
Python1def remove_participant(self, member_id: str) -> bool: 2 if member_id not in self.participants: 3 return False 4 else: 5 del self.participants[member_id] 6 if member_id in self.dishes: 7 del self.dishes[member_id] 8 if member_id in self.votes: 9 del self.votes[member_id] 10 return True
The add_dish
method's logic remained mostly unchanged since it primarily interacts with the dishes
dictionary. However, ensuring that the method checks for the validity of the member_id
against the updated participants' storage is essential.
Participants Data Structure Change: By transitioning from a set to a dictionary for storing participant details, we've inherently kept the unique identification trait while adding the functionality for storing join times. This change is backward compatible as it requires no modification in how participant IDs are provided or handled externally.
Method Signature Consistency: All method signatures (add_participant
, remove_participant
, add_dish
) remain unchanged. This deliberate decision ensures that existing integrations with our system interface seamlessly without modifications from client code.
Combining all our steps, this is the final implementation of our Potluck class with all the required methods:
Python1import time 2 3class Potluck: 4 5 def __init__(self): 6 self.participants = {} 7 self.dishes = {} 8 self.votes = {} 9 10 def add_participant(self, member_id: str) -> bool: 11 if member_id in self.participants: 12 return False 13 else: 14 self.participants[member_id] = time.time() 15 return True 16 17 def remove_participant(self, member_id: str) -> bool: 18 if member_id not in self.participants: 19 return False 20 else: 21 del self.participants[member_id] 22 if member_id in self.dishes: 23 del self.dishes[member_id] 24 if member_id in self.votes: 25 del self.votes[member_id] 26 return True 27 28 def add_dish(self, member_id: str, dish_name: str) -> bool: 29 if member_id not in self.participants or member_id in self.dishes: 30 return False 31 else: 32 self.dishes[member_id] = dish_name 33 return True 34 35 def vote(self, member_id: str, vote_id: str) -> bool: 36 if member_id in self.participants and member_id not in self.votes: 37 self.votes[member_id] = vote_id 38 return True 39 else: 40 return False 41 42 def dish_of_the_day(self) -> str | None: 43 votes = list(self.votes.values()) 44 if not votes: 45 return None 46 vote_count = {i: votes.count(i) for i in votes} 47 max_votes = max(vote_count.values()) 48 max_vote_dishes = [k for k, v in vote_count.items() if v == max_votes] 49 earliest_join_time = min([self.participants[i] for i in max_vote_dishes]) 50 dish_of_the_day_member = [k for k in max_vote_dishes if self.participants[k] == earliest_join_time][0] 51 return f"Participant: '{dish_of_the_day_member}', Dish: '{self.dishes[dish_of_the_day_member]}'"
Bravo! You've successfully completed the task of introducing complex features while preserving backward compatibility. This skill is invaluable in real-life software engineering scenarios, where existing codebases can be thousands or even millions of lines long, and breaking changes can be catastrophic. Strengthen this ability with even more practice and explore similar challenges. I'll see you in the next lesson! Happy coding!